If E, F are two events in a random experiment such that $$P(E) = \frac{1}{2}, P(F) = \frac{1}{3}$$ and $$P(E \cap F) = \frac{1}{12}$$ then $$P(E \cup F) =$$

A

$$\frac{1}{4}$$

B

$$\frac{3}{4}$$

C

$$\frac{5}{6}$$

D

$$\frac{7}{12}$$