A and B are two events such that $$P(A) = \frac{2}{3}, P(\overline{A}\cap B) = \frac{1}{6}$$ and $$P(A\cap B) = \frac{1}{3}$$, ther $$P(\overline{A}\cup B) = $$

A

$$\frac{1}{6}$$

B

$$\frac{1}{2}$$

C

$$\frac{2}{3}$$

D

$$\frac{3}{4}$$