What will come in place of the question mark (?) in the following questions ?
$$(\sqrt{7744}\times11^{2})\div2^{3}=(?)^{3}$$
Let the missing number be y
$$(\sqrt{7744\times 11^2})\div 2^3=(?)^2$$
$$\frac{88\times11}{8}=(y)^2$$
$$121=(y)^2$$
y = 11
Hence the correct option is B
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