If $$m \neq 0, n^{2} \neq 1$$ and $$2^{m^{a^{2}}} = (2^{m})^{n^{2}}$$ then 'm' in terms of 'n' is

A

$$(n^{n^{2 -1}})^{2}$$

B

$$n^{n^{2 -1}}$$

C

$$n^{\left(\frac{1}{n^{2}-1}\right)}$$

D

$$n^{\left(\frac{2}{n^{2}-1}\right)}$$