A class photograph has to be taken. The front row consists of 6 girls who are sitting. 20 boys are standing behind. The two corner positions are reserved for the 2 tallest boys. In how many ways can the students be arranged?
The two boys in corner can be arranged in = $$2!$$ ways
Now, the remaining boys can be arranged in = $$18!$$ ways
There are 6 girls who can be arranged in = $$6!$$ ways
$$\therefore$$ Total number of ways in which all the students can be arranged
= $$2!\times18!\times6!$$
= $$18!\times1440$$
=> Ans - (A)
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