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$$ 2^{4} \times 3^{4} \times 8^{4} \div (2 \times 3 \times 8)^{3} $$ is
$$ 2^{4} \times 3^{4} \times 8^{4} \div (2 \times 3 \times 8)^{3} $$
=$$\frac{2^{16} \times 3^{4}}{2^{12} \times 3^{3}}=2^{4} \times 3=48$$
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