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If $$\sigma$$ is the standard deviation of $$x_1, x_2, x_3, ......, x_n$$ then the standard deviation of observations $$5x_1 - 11, 5x_2 - 11, 5x_3 - 11, ....., 5x_n - 11$$ is
$$5(\sigma - 11)$$
$$5\sigma - 11$$
$$5 \sigma$$
$$\sigma$$
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