A vessel contains 60 litres of milk. 12 liters of milk taken out from it and replaced by water. Then again from mixture. 12 litres are again taken out and replaced by water. The ratio of milk and water in the resultant mixture is:

Initial quantity of milk = 60 litres

When 12 liters of milk taken out from it and replaced by water, then quantity of milk = $$60-12=48$$ litres and water = $$12$$ litres

(Total mixture still remains 60 litres)

Again, 12 litres of mixture is taken out, => Fraction of mixture taken out = $$\frac{12}{60}=\frac{1}{5}^{th}$$

=> Milk left = $$48-(\frac{1}{5}\times48)=38.4$$ litres

=> Water left = $$60-38.4=21.6$$ litres

$$\therefore$$ Required ratio = $$\frac{38.4}{21.6}=\frac{64}{36}=16:9$$

=> Ans - (D)