In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women ?
The number of ways of selecting 5 women from 7 women is $$^7 C_5 = 21$$ ways
The number of ways of selecting 2 women from 3 women is $$^3 C_2 = 3$$ ways
Hence, the total number of ways of selecting is 21*3 = 63 ways.
So, the correct option is option (a)
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