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Question 142
If the difference between the average of x, y and y, z is 12 then the difference between x and z is:
Solution
Average of $$x,y$$ = $$\frac{(x+y)}{2}$$
Average of $$y,z$$ = $$\frac{(y+z)}{2}$$
According to ques,
=> $$(\frac{x+y}{2})-(\frac{y+z}{2})=12$$
=> $$\frac{x-z}{2}=12$$
=> $$(x-z)=12\times2=24$$
=> Ans - (A)
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