Three containers whose volumes are in the ratio of 2 : 3 : 4 are full of mixture of spirit and water. In the 1st container, the ratio of spirit and water is 4: 1, in the 2nd container the ratio is 11 : 4 and in the 3rd container ratio is 7: 3. All the three mixture are mixed in a big container. The ratio of spirit and water in the resultant mixture is :

Let volume of each container be 30, 45, 60 litres respectively.

In 1st container, spirit = $$\frac{4}{(4+1)}\times30=24$$ litres

=> Water = $$30-24=6$$ litres

Similarly, in 2nd container, spirit = 33 litres and water = 12 litres

And in 3rd container, spirit = 42 litres and water = 18 litres

After mixing, total spirit = $$24+33+42=99$$ litres and water = $$6+12+18=36$$ litres

$$\therefore$$ Required ratio = 11 : 4

=> Ans - (B)