Question 142

If $$\sin \theta - \cos \theta = 0, 0^\circ < \theta < 90^\circ$$, then the value of $$\sin^4 \theta + \cos^4 \theta$$ is:

Solution

Given,

$$sin\theta-cos\theta=0$$

$$sin\theta=cos\theta$$

$$sin\theta=sin(90-\theta)$$

$$\theta=90-\theta$$

$$\theta+\theta=90$$

$$2\theta=90$$

$$\theta=45$$

$$sin^4\theta+cos^4\theta$$

$$sin^4(45)+cos^4(45)$$

$$(\dfrac{1}{\sqrt2})^4+(\dfrac{1}{\sqrt2}^4)$$

$$\dfrac{1}{4}+\dfrac{1}{4}$$

$$\dfrac{1}{2}$$


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