Study the following table to answer these questions.
The following table gives the number of candidates appeared (App.) and qualified (Qual.) in ABC entrance examination from different zones (I - VI in different years from 2010-2015).
The numberof students appeared from Zone V in 2012 and 2015_together is approximately what percent less than that from Zone II in 2011 and 2014 together?
Solution
The number of students appeared from Zone V in 2012 and 2015 together = 1143+1203 = 2346
The number of students appeared from Zone II in 2011 and 2014 together = 2899+3698 = 6597
The number of students appeared from Zone V in 2012 and 2015 together is approximately = $$\frac{\left(6597-2346\right)}{6597}\cdot100\ =\ 64.4\%$$ less than that from Zone II in 2011 and 2014 together
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