The length of the median of $$\triangle ABC$$ through B, if the vertices A, B and C are respectively at (4, 2), (6, 5) and (1, 4) is

A

$$\sqrt{65}$$

B

$$\frac{1}{2}\sqrt{65}$$

C

$$\frac{1}{3}\sqrt{65}$$

D

$$\frac{1}{4}\sqrt{65}$$