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The equation of the line passing through (p, q) and having slope as $$\sqrt{3}$$ is
$$y -p = \frac{1}{\sqrt{3}} (x - q)$$
$$y -q = \frac{1}{\sqrt{3}} (x - p)$$
$$y -q = \sqrt{3}(x - p)$$
$$y -p = \sqrt{3}(x - q)$$
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