Question 14
Two box types $$A$$ and $$B$$ hold $$38$$ and $$20$$ candles respectively. Exactly $$288$$ candles fill all the boxes. If $$m$$ boxes are of type $$A$$ and $$n$$ boxes are of type $$B$$, then $$\frac{m}{n}$$ is
Solution
The equation is $$38m+20n=288$$, or $$19m+10n=144$$. The positive integer solution is $$m=6$$ and $$n=3$$. Therefore, $$\frac{m}{n}=\frac{6}{3}=2$$.
Get AI Help
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Session:Free CAT Mentorship
Phone:
Date:
Time:
Enter OTP
Didn't receive the OTP?
