In each of these questions, two equations are given. You have to solve these equations and nd out the values of x and y and :
Give answer
a:if x < y
b: if x > y
c: if x ≤ y
d: if x ≥ y
e: if x = y
I. $$18x^{2}+ 18x + 4 = 0$$
II.$$12y^{2}+29y+14=0$$
I : $$18x^{2} + 18x + 4 = 0$$
=> $$18x^2 + 6x + 12x + 4 = 0$$
=> $$6x (3x + 1) + 4 (3x + 1) = 0$$
=> $$(6x + 4) (3x + 1) = 0$$
=> $$x = \frac{-2}{3} , \frac{-1}{3}$$
II : $$12y^{2} + 29y + 14 = 0$$
=> $$12y^2 + 8y + 21y + 14 = 0$$
=> $$4y (3y + 2) + 7 (3y + 2) = 0$$
=> $$(4y + 7) (3y + 2) = 0$$
=> $$y = \frac{-2}{3} , \frac{-7}{4}$$
$$\therefore x \geq y$$
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