Instructions

In each of these questions, two equations are given. You have to solve these equations and nd out the values of x and y and :
Give answer
a:if x < y
b: if x > y
c: if x ≤ y
d: if x ≥ y
e: if x = y

Question 13

I. $$17x^{2} + 48x= 9$$
II. $$13y^{2} = 32y- 12$$

Solution

I : $$17x^{2} + 48x - 9 = 0$$

=> $$17x^2 + 51x - 3x - 9 = 0$$

=> $$17x (x + 3) - 3 (x + 3) = 0$$

=> $$(17x - 3) (x + 3) = 0$$

=> $$x = -3 , \frac{3}{17}$$

II : $$13y^{2} - 32y + 12 = 0$$

=> $$13y^2 - 26y - 6y + 12 = 0$$

=> $$13y (y - 2) - 6 (y - 2) = 0$$

=> $$(13y - 6) (y - 2) = 0$$

=> $$y = 2 , \frac{6}{13}$$

$$\therefore x < y$$

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I. $$17x^{2} + 48x= 9$$II. $$13y^{2} = 32y- 12$$

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I. $$17x^{2} + 48x= 9$$
II. $$13y^{2} = 32y- 12$$