In each of these questions, two equations are given. You have to solve these equations and nd out the values of x and y and :
Give answer
a:if x < y
b: if x > y
c: if x ≤ y
d: if x ≥ y
e: if x = y
I. $$16x^{2} + 20x + 6 = 0$$
II. $$10y^{2} + 38y + 24 = 0$$
I : $$16x^{2} + 20x + 6 = 0$$
=> $$16x^2 + 8x + 12x + 6 = 0$$
=> $$8x (2x + 1) + 6 (2x + 1) = 0$$
=> $$(8x + 6) (2x + 1) = 0$$
=> $$x = \frac{-3}{4} , \frac{-1}{2}$$
II : $$10y^{2} + 38y + 24 = 0$$
=> $$10y^2 + 30y + 8y + 24 = 0$$
=> $$10y (y + 3) + 8 (y + 3) = 0$$
=> $$(10y + 8) (y + 3) = 0$$
=> $$y = -3 , \frac{-4}{5}$$
$$\therefore x > y$$
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