$$32\frac{3}{4}+28\frac{1}{2}\times5\frac{1}{3}-12\frac{1}{6}=?+5\frac{1}{4}$$

Solution

Expression : $$32\frac{3}{4}+28\frac{1}{2}\times5\frac{1}{3}-12\frac{1}{6}=?+5\frac{1}{4}$$

=> $$\frac{131}{4} + (\frac{57}{2} \times \frac{16}{3}) - \frac{73}{6} = ? + \frac{21}{4}$$

=> $$? = \frac{131}{4} + 152 - \frac{73}{6} - \frac{21}{4}$$

=> $$? = 152 + \frac{393 - 146 - 63}{12}$$

=> $$? = 152 + \frac{46}{3} = 152 + 15\frac{1}{3}$$

=> $$? = 167\frac{1}{3}$$

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