The number of electrons delivered at the cathode during electrolysis by a current of lampere in 60 seconds is (charge on electron $$= 1.60 \times 10^{-19}$$ C)

A

$$6 \times 10^{20}$$

B

$$3.75 \times 10^{20}$$

C

$$7.48 \times 10^{23}$$

D

$$6 \times 10^{23}$$