Question 139
The area (in sq. units) of the triangle formed by the points (0, 0), (2, -3) and (4, 5) is
Solution
Area of the triangle when one vertex is origin is $$\frac{1}{2}\left|x_2y_3-x_3y_2\right|$$ = $$\frac{1}{2}\left|2\cdot5\ -\ \left(4\right)\cdot\left(-3\right)\right|=11$$
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