If A(3, 10), B (-3, 4) and C (5, 8) are the vertices of a $$\triangle ABC$$ and AD and CF are its medians. then the ratio of the length of AD to the length of CF is

A

$$\sqrt{10} : \sqrt{13}$$

B

$$\sqrt{12} : \sqrt{13}$$

C

$$\sqrt{10} : \sqrt{9}$$

D

$$\sqrt{10} : \sqrt{15}$$