Solution
$$\triangle{ABC}$$ is an equilateral triangle,
$$\angle{OAC}=\frac{\angle{BAC}}{2}$$ (In equilateral triangle medians and angle bisectors are same)
$$=30$$
Similarly,
$$\angle{OCA}=30$$
In $$\triangle{OAC}$$,
$$\angle{AOC}+\angle{OAC}+\angle{OCA}=180$$
$$\angle{AOC}+30+30=180$$
$$\angle{AOC}=120$$
Hence,Option C is correct.
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