Question 139

A circular road runs around a circular ground. If the difference between the circumferences of the outer circle and the inner circle is 66 metres, the width of the road is:

Solution

Let the radius of outer circle be $$R$$ and of smaller circle be $$r$$

Width of road = $$(R - r)$$ = ?

Acc to ques :

=> $$2\pi R - 2\pi r = 66$$

=> $$R - r = \frac{33}{\pi}$$

=> $$R - r = \frac{33 * 7}{22} = 10.5 m$$

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