Question 138

The perimeter of the base of a right circular cone is 8 cm. If the height of the cone is 21 cm, then its volume is:

Solution

Let the radius of the cone be $$r$$ and height = 21

=> Perimeter of base = $$2 \pi r = 8$$

=> $$r = \frac{4}{\pi}$$

Volume of cone = $$\frac{1}{3} \pi r^2 h$$

= $$\frac{1}{3} \pi (\frac{4}{\pi})^2 21$$

= $$\frac{112}{\pi} cm^3$$

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