If $$x \left(3 - \frac{2}{x}\right) = \left(\frac{3}{x}\right)$$ then value of $$x^{2} + \frac{1}{x^{2}}$$ is

A

$$1\frac{1}{9}$$

B

$$2\frac{4}{9}$$

C

$$3 \frac{5}{9}$$

D

$$4 \frac{7}{9}$$