Question 138

If the positions corresponding to the multiples of five in the following alphabet are replaced by symbols and that of multiples of seven by digits, how many letters will be left ?
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

Solution

There are 26 alphabets positioned 1 to 26

Numbers which are multiples of 5 (till 26) = 5, 10, 15, 20, 25

Similarly, there will be 3 multiples of 7

Thus, total letters replaced by symbols and digits = 5 + 3 = 8

=> Letters left = 26 - 8 = 18

=> Ans - (B)

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