Question 138

$$5tan\theta = 4$$, then the value of $$(\frac{5sin\theta - 3cos\theta}{5sin\theta + 3cos\theta})$$ is

Taking $$cos\theta$$ outside in numerator and in denominator and making $$tan\theta$$
hence eq will be  $$(\frac{5tan\theta - 3}{5tan\theta + 3})$$
As it is given that $$5tan\theta$$ = 4
after putting values and solving we will get the equation reduced to 1/7.

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