If x,y are positive acute angles, x + y < 90o and sin(2x -20o) = cos(2y + 20o), then the values of sec(x + y) is
Given sin(2x-20) = cos(2y+20)
as x and y are positive acute angles
hence cos(90-2x+20) = cos(2y+20)
or 90-2x+20 = 2y+20
or x+y = 45
or sec(x+y) = $$\sqrt2$$
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