A rectangular sheet of paper which is 88 cm long and 11 cm wideis rolled to form a cylinderof height equal to its width of the paper. What is the volumeofthe cylinder so formed?

length of paper, h=88cm

width of paper,b=11cm

height of cylinder,H=width of paper=11cm.

let radiud of base of cylinder be r cm.

circumference of base of cylinder=height of paper=88cm.

$$\rightarrow2\pi r=88$$

$$\rightarrow 2\times \dfrac{22}{7}\times r=88$$

$$\rightarrow r=\dfrac{88\times7}{44}$$

$$\rightarrow r= 14$$cm

volume of cylinder$$V=\pi r^2h$$

$$\rightarrow,V=\dfrac{22\times14^2\times11}{7}$$

$$\rightarrow,V=6776cm^3$$