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The external bisector of $$\angle B$$ and $$\angle C$$ of $$\angle ABC$$ (where AB and AC extended to E and F respectively) meet at point P. If $$\angle BAC = 100^\circ$$, then the measure of $$\angle BPC$$ is
$$50^\circ$$
$$80^\circ$$
$$40^\circ$$
$$100^\circ$$
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