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Instructions
What will come in place of the question mark (?) in the following number series ?
Solution
The pattern here is,
$$54+(1^{2}+1) = 54+2 = 56$$.
$$56+(2^{2}+1) = 56+5 =61$$.
$$61+(3^{2}+1) = 61+10 = 71$$.
$$71+(4^{2}+1) = 71+17 = 88$$.
$$88+(5^{2}+1) = 88+26 = 114$$.
Hence, Option C is correct.
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