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$$y = \cot^{-1}\left(\frac{1 - 3x^2}{3x - x^3}\right) \Rightarrow \frac{dy}{dx} =$$
$$-\frac{3}{1 + x^2}$$
$$\frac{3}{1 + x^2}$$
$$\frac{3}{1 - x^2}$$
$$-\frac{3}{1 - x^2}$$
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