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Solution
$$2^{x-1} + 2^{x+1} = 320$$
=> $$\frac{2^{x}}{2} + 2^{x}.2 = 320$$
Let $$2^{x} = y$$
=> $$\frac{y}{2} + 2y = 320$$
=> $$5y = 640 => y = 128$$
Now, $$2^{x} = 128 = 2^{7}$$
=> $$x = 7$$
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