Question 135

If $$2^{x-1} + 2^{x+1} = 320$$, then the value of x is

Solution

$$2^{x-1} + 2^{x+1} = 320$$

=> $$\frac{2^{x}}{2} + 2^{x}.2 = 320$$

Let $$2^{x} = y$$

=> $$\frac{y}{2} + 2y = 320$$

=> $$5y = 640 => y = 128$$

Now, $$2^{x} = 128 = 2^{7}$$

=> $$x = 7$$

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