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The inverse of the statement $$p \rightarrow (q \wedge r)$$ is
$$(\sim q)\vee (\sim r) \rightarrow \sim p$$
$$\sim p \rightarrow (\sim q) \wedge (\sim r)$$
$$q \wedge r \rightarrow p$$
$$\sim p \rightarrow (\sim q) \vee (\sim r)$$
Solution:
inverse of $$p \rightarrow (q \wedge r)$$
~(p -> (q^r))
~ p -> ~(q^r)
~ p ->(~q) v (~r) Answer
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