Question 134

If 146! is divisble by $$5^{n}$$, then find the maximum value of n

The maximum value of n will be equal to the number of powers of 5 in the expansion of 146!.
This will be equal to whole number values of: $$\frac{146}{5}+\frac{29}{5}+\frac{5}{5}=29\ +\ 5\ +\ 1\ =\ 35$$.
So, the maximum value that n can take is 35.

Need AI Help?

Create a FREE account and get:

  • Download Maths Shortcuts PDF
  • Get 300+ previous papers with solutions PDF
  • 500+ Online Tests for Free

Join CAT 2026 course by 5-Time CAT 100%iler

Crack CAT 2026 & Other Exams with Cracku!

Ask AI

Ask our AI anything

AI can make mistakes. Please verify important information.