If $$\frac{5x}{2x^2+5x+1}=\frac{1}{3}$$ then the value of $$(x+\frac{1}{2x})$$ is
Expression : $$\frac{5x}{2x^2+5x+1}=\frac{1}{3}$$
=> $$2x^2 + 5x + 1 = 15x$$
=> $$2x^2 + 1 = 10x$$
To find : $$(x+\frac{1}{2x})$$
= $$\frac{2x^2 + 1}{2x}$$
= $$\frac{10x}{2x}$$
= 5
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