If $$\ \frac{3x-1}{x}+\frac{5y-1}{y}+\frac{7z-1}{z}$$= 0, then what is the value of $$\ \frac{1}{x}+\frac{1}{y}+\frac{1}{z}\ $$?
Given : $$\ \frac{3x-1}{x}+\frac{5y-1}{y}+\frac{7z-1}{z}=0$$
=> $$(3-\frac{1}{x})+(5-\frac{1}{y})+(7-\frac{1}{z})=0$$
=> $$\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=3+5+7$$
=> $$\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=15$$
=> Ans - (C)
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