Let $$ A = \begin{bmatrix}0 & \alpha \\\beta & 0 \end{bmatrix}, \alpha \neq 0, \beta \neq 0$$. If $$A^3 + A = 0$$, then $$\alpha \beta =$$

A

1

B

$$\frac{1}{2}$$

C

$$-\frac{1}{2}$$

D

-1