Question 131
Four years ago a man was 6 times as old as his son. After 16 years he will be twice as old as his son. What is the present age of man and his son?
Solution
Let us assume the present ages of the father and son to be F and S respectively.
Four years ago the man was 6 times as old as his son: F-4 = 6(S-4) ==> 6S - F = 20.
After 16 years he will be twice as old as his son: F+16 = 2(S+16) ==> F - 2S = 16.
Adding both equations, we get 4S = 36 ==> S = 9 and F = 34.
Get AI Help
Create a FREE account and get:
- Download Maths Shortcuts PDF
- Get 300+ previous papers with solutions PDF
- 500+ Online Tests for Free
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Session:Free CAT Mentorship
Phone:
Date:
Time:
Enter OTP
Didn't receive the OTP?
