Question 131

Among three numbers, the first is twice the second and thrice the third. If the average of the three numbers is 49.5, then the difference between the first and the third number is

Solution

average = $$\frac{Sum}{NumberofElements}$$

here average of three numbers = 49.5

Sum = 49.5 x 3 = 148.5

let the first number be y and hence 2nd number be y/2 and third number be y/3

here, y + y/2 + y/3 = 148.5

11y/6 = 148.5

1st number = y = 13.5 x 6 = 81

3rd number = y/3 = 27

difference between 1st and 2nd number = 81 - 27 = 54

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