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A and B are the end points of a diameter of a circle whose radius is 3 cm. If C is a point on the circle such that AC = CB, then the perimeter (in cms) of the $$\angle$$ ABC is
$$6 + 6\sqrt{2}$$
$$3 + 3\sqrt{2}$$
$$6 + 3\sqrt{2}$$
$$6 + 3\sqrt{3}$$
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