Question 130

The internal angle between two adjacent sides of a regular pentagon in radians is

Solution

Sum of interior angles =Β S = (n - 2)*180Β 

S = (5-2) X 180 = 540

Each interior angle = 540/5 = 108

in radiansΒ $$\frac{108}{180}\ \pi\ \ radian\ =\ \frac{3}{5}\pi\ radian$$Β Answer

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