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The internal angle between two adjacent sides of a regular pentagon in radians is
Solution
Sum of interior angles =Β S = (n - 2)*180Β
S = (5-2) X 180 = 540
Each interior angle = 540/5 = 108
in radiansΒ $$\frac{108}{180}\ \pi\ \ radian\ =\ \frac{3}{5}\pi\ radian$$Β Answer
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