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$$\frac{\text{d}}{\text{d}x}{(\cos(3\log_e x))} =$$
we will use chain rule, moving inwards
there are 3 functions in the form: cos K, 3M, and log Z
For cos K differentiation, -sin K = -sin (3log x)........where K = (3 logx)
For 3M , differentiation, =3 ..................
For log z, differentiation = 1/z = 1/x
Combining all the three
$$\frac{\text{d}}{\text{d}x}{(\cos(3\log_e x))} =$$ = {-sin (3log x)}{-3}{1/x} =
Answer
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