If the lengths ofthe side and one diagonal of a rhombus are respectively 13 cm and 10 cm, then the area of the rhombus in square centimeters is
Soution:
The diagonals of rhombus form right angle at the centre.
AO = 10/2 = 5 cm
AD = 13 cm
So DO = $$\sqrt{\ \left(AD^2\right)\ -\ \left(AO^2\right)}$$
= $$\sqrt{\ \left(13^2\right)\ -\ \left(5^2\right)}\ =12\ cm$$
Length of diagonal = 24
Area of diagonals = $$\frac{1}{2\ }\Pr oduct\ of\ diagonals\ =\ \frac{1}{2\ }\times\ \ 10\ \times24\ =120\ cm^2\ $$
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