AP ICET 26th April 2019 Shift-2

Question 130

The $$9^{th}$$ term in the binomial expansion of $$\left(x - \frac{1}{x}\right)^{17}$$ is

Solution

kth term of series $$\left(x+a\right)^n\ =\ n_{c_{k-1}}\left(x\right)^{n-\left(k-1\right)}\left(a\right)^{k-1}$$

$$9^{th}$$ term in the binomial expansion of $$\left(x - \frac{1}{x}\right)^{17}$$ = $$\ 17_{c_8}x^9\left(-\frac{1}{x}\right)^8=17_{c_8}x$$


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