Instructions

Study the following information carefully to answer the questions that follow : 

There are two Trains, Train-A and Train-B. Both Trains have four different types of Coaches viz. General Coaches, Sleeper Coaches, First Class Coaches and AC Coaches. In Train A there are total 700 passengers. Train-B has thirty percent more passengers than Train A. Twenty percent of the passengers of Train-A are in General Coaches. One-fourth of the total number of passengers of Train-A are in AC coaches. Twenty three percent of the passengers of Train-A are in Sleeper Class Coaches. Remaining passengers of Train-A are in first class coaches. Total number of passengers in AC coaches in both the trains together is 480. Thirty percent of the number of passengers of Train-B is in Sleeper Class Coaches. Ten percent of the total passengers of Train-B are in first class coaches. Remaining passengers of Train-B are in general class coaches.

Question 129

Total number of passengers in General Class coaches in both the Trains together is approximately what percentage of total number of passengers in Train-B ?

Solution

Total passengers in train A = 700

=> Total passengers in train B = $$\frac{130}{100} \times 700 = 910$$

Number of passengers In train A in the class :

General = $$\frac{20}{100} \times 700 = 140$$

AC = $$\frac{1}{4} \times 700 = 175$$

Sleeper = $$\frac{23}{100} \times 700 = 161$$

First = $$700 - 140 - 175 - 161 = 224$$

Number of passengers in train B in the class :

AC = $$480 - 175 = 305$$

Sleeper = $$\frac{30}{100} \times 910 = 273$$

First = $$\frac{10}{100} \times 910 = 91$$

General = $$910 - 305 - 273 - 91 = 241$$

Total number of passengers in General Class coaches in both the Trains together = 140 + 241 = 381

Total number of passengers in Train-B = 910

=> Required % = $$\frac{381}{910} \times 100$$

= $$41.86 \% \approx 42 \%$$


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