Study the following information carefully to answer the questions that follow :
There are two Trains, Train-A and Train-B. Both Trains have four different types of Coaches viz. General Coaches, Sleeper Coaches, First Class Coaches and AC Coaches. In Train A there are total 700 passengers. Train-B has thirty percent more passengers than Train A. Twenty percent of the passengers of Train-A are in General Coaches. One-fourth of the total number of passengers of Train-A are in AC coaches. Twenty three percent of the passengers of Train-A are in Sleeper Class Coaches. Remaining passengers of Train-A are in first class coaches. Total number of passengers in AC coaches in both the trains together is 480. Thirty percent of the number of passengers of Train-B is in Sleeper Class Coaches. Ten percent of the total passengers of Train-B are in first class coaches. Remaining passengers of Train-B are in general class coaches.
Total number of passengers in General Class coaches in both the Trains together is approximately what percentage of total number of passengers in Train-B ?
Total passengers in train A = 700
=> Total passengers in train B = $$\frac{130}{100} \times 700 = 910$$
Number of passengers In train A in the class :
General = $$\frac{20}{100} \times 700 = 140$$
AC = $$\frac{1}{4} \times 700 = 175$$
Sleeper = $$\frac{23}{100} \times 700 = 161$$
First = $$700 - 140 - 175 - 161 = 224$$
Number of passengers in train B in the class :
AC = $$480 - 175 = 305$$
Sleeper = $$\frac{30}{100} \times 910 = 273$$
First = $$\frac{10}{100} \times 910 = 91$$
General = $$910 - 305 - 273 - 91 = 241$$
Total number of passengers in General Class coaches in both the Trains together = 140 + 241 = 381
Total number of passengers in Train-B = 910
=> Required % = $$\frac{381}{910} \times 100$$
= $$41.86 \% \approx 42 \%$$
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