Question 128

If $$Sin\ 2\theta=\frac{\sqrt{3}}{2}$$ then the value of $$Sin\ 3\theta$$ is equal to: $$(Take\ 0^\circ \leq \theta \leq 90^\circ)$$

Solution

Given : $$Sin\ 2\theta=\frac{\sqrt{3}}{2}$$

=> $$Sin\ 2\theta=sin(60^\circ)$$

=> $$2\theta=60^\circ$$

=> $$\theta=\frac{60}{2}=30^\circ$$

To find : $$sin\ 3\theta$$

= $$sin(3\times30^\circ)$$

= $$sin(90^\circ)=1$$

=> Ans - (C)

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