In the given figure $$\triangle ABC$$, if $$\angle BEC = 90^{\circ}$$, $$\angle EBD=4O^{\circ}$$ and $$\angle DAC = 30^{\circ}$$, then $$x+y$$ =

A

$$110^{\circ}$$

B

$$120^{\circ}$$

C

$$130^{\circ}$$

D

$$140^{\circ}$$